# Three workers

The three workers received € 2,850 together for the work done. They divided them according to the time worked so that the first received 20% less than the second and the third € 50 more than the second. How much EUR did each worker receive?

Correct result:

a =  800
b =  1000
c =  1050

#### Solution:

a+b+c= 2850
a= b-0.20b
c = 50+b

a+b+c= 2850
a= b-0.20•b
c = 50+b

a+b+c = 2850
a-0.8b = 0
b-c = -50

a = 800
b = 1000
c = 1050

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