Hole's angles

I am trying to find an angle. The top of the hole is .625” and the bottom of the hole is .532”. The hole depth is .250” what is the angle of the hole (and what is the formula)?

Result

A =  79.463 °

Solution:

a=0.625 c=0.532 h=0.250  x=(ac)/2=(0.6250.532)/2=932000=0.0465  tanA=h:x A1=arctan(h/x)=arctan(0.25/0.0465)1.3869 A=A1 =A1 180π  =79.4633920571  =79.463=792748"a = 0.625 \ \\ c = 0.532 \ \\ h = 0.250 \ \\ \ \\ x = (a-c)/2 = (0.625-0.532)/2 = \dfrac{ 93 }{ 2000 } = 0.0465 \ \\ \ \\ \tan A = h:x \ \\ A_{ 1 } = \arctan(h/x) = \arctan(0.25/0.0465) \doteq 1.3869 \ \\ A = A_{ 1 } \rightarrow \ ^\circ = A_{ 1 } \cdot \ \dfrac{ 180 }{ \pi } \ \ ^\circ = 79.4633920571 \ \ ^\circ = 79.463 ^\circ = 79^\circ 27'48"







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