Tower's view

From the church tower's view at 65 m, the top of the house can be seen at a depth angle of alpha = 45° and its bottom at a depth angle of beta = 58°. Calculate the house's height and its distance from the church.

Final Answer:

y =  24.3835 m
x =  40.6165 m

Step-by-step explanation:

$$\begin{gathered} h=65\text{m} \\ \alpha =45{}^{\circ } \\ \beta =58{}^{\circ } \\ \tan \beta =h:x \\ x=h/\tan \beta =h/\tan 58°=65/\tan 58°=65/1.600335=40.61651\text{m} \\ \tan \alpha =(h-y):x \\ y=h-x\cdot \tan \alpha =h-x\cdot \tan 45°=65-40.6165\cdot \tan 45°=65-40.6165\cdot 1=24.383=24.3835\text{m} \end{gathered}$$

$x=40.6165=40.6165\text{m}$

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