From the aircraft flying at an altitude of 500m, they observed places A and B (located at the same altitude) in the direction of flight at depth angles alpha = 48° and beta = 35°. What is the distance between places A and B?

Correct answer:

x =  263.872 m

Step-by-step explanation:

h=500 m α=48 β=35  tanα=h:x1 tanβ=h:x2  x1=h/tanα=h/tan48 =500/tan48 =500/1.110613=450.20202 m x2=h/tanβ=h/tan35 =500/tan35 =500/0.700208=714.074 m  x=x2x1=714.074450.202=263.872 m

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