The triangles

The triangles ABC and A'B'C 'are similar with a similarity coefficient of 2. The angles of the triangle ABC are alpha = 35°, beta = 48°. Determine the magnitudes of all angles of triangle A'B'C '.

Correct result:

A₂ =  35 °
B₂ =  48 °
C₂ =  97 °

Solution:

$$\begin{gathered} \alpha =35^{\circ } \\ \beta =48^{\circ } \\ k=2 \\ {A}_2=\alpha =35=35^{\circ } \end{gathered}$$

$B_2=\beta =48=48^{\circ }$

$$\begin{gathered} \alpha +\beta +\gamma =180^{\circ } \\ {C}_2=180-A_2-B_2=180-35-48=97^{\circ } \end{gathered}$$

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