# Aircrafts

Above the town hall tower flew the plane with constant speed 592 km/h and 15 minutes later the second plane at speed of 675 km/h. How long and how far from the town hall will be aircrafts caught up?

Result

t =  107 min
s =  1203.614 km

#### Solution:

$592\cdot (t+15) = 675\cdot t \ \\ s = 675/60\cdot t \ \\ \ \\ t = \dfrac{ 592}{ 675-592} \cdot 15 = 107 \ \text{ min } \ \\ s = 675/60 \cdot t = 11.25 \cdot 107 \ \text{ min } = 1203.61 \ km$

592*(t+15) = 675*t
s = 675/60*t

83t = 8880
60s-675t = 0

s = 9990083 ≈ 1203.614458
t = 888083 ≈ 106.987952

Calculated by our linear equations calculator.

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