Positional energy

What velocity in km/h must a body weighing 60 kg have for its kinetic energy to be the same as its positional energy at the height 50 m?

Correct result:

v =  112.7553 km/h

Solution:

m=60 kg h=50 m g=9.81 m/s2  E=m⋅ g⋅ h=60⋅ 9.81⋅ 50=29430 J  E=12mv2  v1=2⋅ Em=2⋅ 2943060=3 109 m/s≐31.3209 m/s  v=v1→ km/h=v1⋅ 3.6  km/h=31.3209195267⋅ 3.6  km/h=112.755 km/h=112.7553 km/h

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