Two integers

Two integers, a and b, have a product of 36. What is the least possible sum of a and b?

Correct result:

s1 =  -37
s2 =  12

Solution:

ab=36 s1=(36)+(1)=37
ab=36  a1=1,b1=36,s1=37 a2=2,b2=18,s2=20 a3=3,b3=12,s3=15 a4=4,b4=9,s4=13 a5=6,b5=6,s5=12 a6=9,b6=4,s6=13 a7=12,b7=3,s7=15 a8=18,b8=2,s8=20 a9=36,b9=1,s9=37  a=36=6 b=36/a=36/6=6 s2=a+b=6+6=12



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