# Examination

The class is 21 students. How many ways can choose two to examination?

Result

n =  210

#### Solution:

$n = C_{{ 2}}(21) = \dbinom{ 21}{ 2} = \dfrac{ 21! }{ 2!(21-2)!} = \dfrac{ 21 \cdot 20 } { 2 \cdot 1 } = 210$

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