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On the menu are 12 kinds of meal. How many ways can we choose four different meals into the daily menu?

Correct answer:

n =  495

Step-by-step explanation:

$$\begin{gathered} C_4(12)=\left({\displaystyle \genfrac{}{}{0px}{}{12}{4}}\right)={\displaystyle \frac{12!}{4!(12-4)!}}={\displaystyle \frac{12\cdot 11\cdot 10\cdot 9}{4\cdot 3\cdot 2\cdot 1}}=495 \\ n=\left(\genfrac{}{}{0px}{}{12}{4}\right)=495=495 \end{gathered}$$

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