Product selection ways

There are 11 products in the box, of which just four are defective. How many ways can we choose five products so that at least four are not faulty?

Final Answer:

n =  49

Step-by-step explanation:

n=(114) (1141) (1142) (1143) (114)/5!=49



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You need to know the following knowledge to solve this word math problem:

combinatoricsarithmeticbasic operations and conceptsGrade of the word problem

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