In the shipment

There are 40 products in a shipment, of which 4 are defective. In how many ways can 5 products be selected so that exactly 3 of them are non-defective?

Final Answer:

n =  42840

Step-by-step explanation:

C3(36)=(336)=3!(363)!36!=321363534=7140 n1=(3404)=7140 C2(4)=(24)=2!(42)!4!=2143=6  n2=(24)=6  n=n1 n2=7140 6=42840



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You need to know the following knowledge to solve this word math problem:

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