Doug biked

Doug biked 5 1/4 miles in 3/4 of an hour. What is his average speed?

Result

a =  7 mil/h

Solution:

$s = 5 + \dfrac{ 1 }{ 4 } = \dfrac{ 21 }{ 4 } = 5.25 \ mil \ \\ t = 3/4 = \dfrac{ 3 }{ 4 } = 0.75 \ h \ \\ \ \\ a = s/t = 5.25/0.75 = 7 = 7 \ \text{ mil/h }$

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