Four legs of journey

A car driver covers a distance between two cities at a speed of 60 kmph and on the return, his speed is 40 kmph. He goes again from the first to the second city at twice the original speed and returns at half the original return speed. Find his average speed for the entire journey.

Correct answer:

v =  40 km/h

Step-by-step explanation:

v1=60 km/h v2=40 km/h v3=2 v1=2 60=120 km/h v4=v2/2=40/2=20 km/h  v = t4d  v =  t1+t2+t3+t44d  s=vt  t1 = d/v1  v =  d/v1+d/v2+d/v3+d/v44d  v=1/v1+1/v2+1/v3+1/v44=1/60+1/40+1/120+1/204=40 km/h



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