Ružomberok 31281

A passenger car traveled the route from Trencin to Ruzomberok in 1 hour and 48 minutes. These two cities are 144 km apart. How many minutes would the driver shorten his return trip if he traveled an average of 90 km per hour?

Correct answer:

t =  12 min

Step-by-step explanation:

t1=1+48/60=59=1.8 h s=144 km v2=90 km/h  t2=s/v2=144/90=58=1.6 h  t3=t1t2=1.81.6=51=0.2 h  t=t3 min=t3 60  min=0.2 60  min=12 min=12 min



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