Pairs of socks

Ferdinand has twelve pairs of socks, one sock is leaky. What is the probability of putting on a leaky sock?

Result

p =  4.167 %

Solution:

p=100⋅ 1⋅ 1112⋅ 11/2=256≐4.1667=4.167%p = 100 \cdot \ \dfrac{ 1 \cdot \ 11 }{ 12 \cdot \ 11 } / 2 = \dfrac{ 25 }{ 6 } \doteq 4.1667 = 4.167 \%

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