Parcel

Both dimensions of the rectangular parcel were increased by 26%. By how many % has increased its acreage?

Result

x =  58.76 %

Solution:

 S1=ab S2=(1.26a)(1.26b)=1.262ab=1.262S1=1.5876S1  x=100(S2S1)/S1=100(1.2621)=58.76% \ \\ S_1 = ab \ \\ S_2 = (1.26 a)(1.26 b) = 1.26^2 ab = 1.26^2 S_1 = 1.5876 S_1 \ \\ \ \\ x = 100 (S_2 - S_1)/S_1 = 100( 1.26^2-1) = 58.76 \%



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