Hop-garden

The length of the rectangular hop garden Mr. Smith increased by 25% and its width by 30%. What is the percentage change in area of hop garden?

Result

p =  62.5 %

Solution:

p1=100%+25%=1.25 p2=100%+30%=1.3 p=100(p1p21)=62.5%p_1 = 100 \% + 25 \% = 1.25 \ \\ p_2 = 100 \% + 30 \% = 1.3 \ \\ p = 100\cdot (p_1 \cdot p_2 -1 ) = 62.5 \%



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