Perimeter of the circle

Calculate the perimeter of the circle in dm, whose radius equals the side of the square containing 0.49 dm2?

Result

o =  4.398 dm

Solution:

S=0.49 dm2 a=S=0.49=710=0.7 dm  r=a=0.7=710=0.7 dm  o=2π r=2 3.1416 0.74.39824.398 dmS=0.49 \ \text{dm}^2 \ \\ a=\sqrt{ S }=\sqrt{ 0.49 }=\dfrac{ 7 }{ 10 }=0.7 \ \text{dm} \ \\ \ \\ r=a=0.7=\dfrac{ 7 }{ 10 }=0.7 \ \text{dm} \ \\ \ \\ o=2 \pi \cdot \ r=2 \cdot \ 3.1416 \cdot \ 0.7 \doteq 4.3982 \doteq 4.398 \ \text{dm}



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