Combinations

How many different combinations of two-digit number divisible by 4 arises from the digits 3, 5 and 7?

Correct answer:

n =  6

Step-by-step explanation:

$$\begin{gathered} n_1=32 \\ {n}_2=36 \\ {n}_3=52 \\ {n}_4=56 \\ {n}_5=72 \\ {n}_6=76 \\ n=6=6 \end{gathered}$$

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