Divisible by five

How many different three-digit numbers divisible by five can we create from the digits 2, 4, 5? The digits can be repeated in the created number.

Correct result:

n =  9

Solution:

$$\begin{gathered} \{2,4,5\}\cdot \{2,4,5\}\cdot \{5\} \\ n=3\cdot 3\cdot 1=9 \end{gathered}$$

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