Newtonmeters

The driver loosened the nut on the car wheel with a wrench that held 20 cm from the axis of the bolt. He acted on the key with a force of 320N. At what moment did he act on the bolt?

Result

M =  64 Nm

Solution:

r=20 cm=20/100 m=0.2 m F=320 N  M=F⋅ r=320⋅ 0.2=64 Nmr=20 \ cm=20 / 100 \ m=0.2 \ m \ \\ F=320 \ \text{N} \ \\ \ \\ M=F \cdot \ r=320 \cdot \ 0.2=64 \ \text{Nm}

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