Newtonmeters

The driver loosened the nut on the car wheel with a wrench that held 20 cm from the axis of the bolt. He acted on the key with a force of 320N. At what moment did he act on the bolt?

Correct result:

M =  64 Nm

Solution:

$$\begin{gathered} r=20\text{ cm}\to \text{ m}=20\mathrm{/}100\text{ m}=0.2\text{ m } \\ F=320\text{ N } \\ M=F\cdot r=320\cdot 0.2=64\text{ Nm} \end{gathered}$$

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