# Newtonmeters

The driver loosened the nut on the car wheel with a wrench that held 20 cm from the axis of the bolt. He acted on the key with a force of 320N. At what moment did he act on the bolt?

Result

M =  64 Nm

#### Solution:

$r=20 \ cm=20 / 100 \ m=0.2 \ m \ \\ F=320 \ \text{N} \ \\ \ \\ M=F \cdot \ r=320 \cdot \ 0.2=64 \ \text{Nm}$

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