Steering 8186

What force does the driver exert when turning on the steering wheel if the steering wheel diameter is 35 cm and the torque is 3.5 N. M?

Correct answer:

F =  20 N

Step-by-step explanation:

D=35 cm m=35:100  m=0.35 m M=3.5 Nm  r=D/2=0.35/2=407=0.175  M = Fr  F=M/r=3.5/0.175=20 N



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