The front wheel of velocipede from year 1880 had a diameter 1.8 m. If the front wheel turned again one then rear wheel 6 times. What was the diameter of the rear wheel?

Correct result:

D2 =  0.3 m


s1=s2 πD1=nπD2 D1=nD2  D2=1.8/6=0.3 ms_1 = s_2 \ \\ \pi D_1 = n \pi D_2 \ \\ D_1 = n D_2 \ \\ \ \\ D_2 = 1.8/6 = 0.3 \ \text{m}

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