Average speed

The average speed of a pedestrian who walked 10 km was 5km/h, the average speed of a cyclist on the same track was 20km/h. In how many minutes did the route take more than a cyclist? Q

Correct result:

x =  90 min

Solution:

$$\begin{gathered} s=10\text{ km } \\ {v}_1=5\text{ km/h } \\ {v}_2=20\text{ km/h } \\ t=t_1-t_2 \\ {t}_1=s\mathrm{/}{v}_1=10\mathrm{/}5=2\text{ h } \\ {t}_2=s\mathrm{/}{v}_2=10\mathrm{/}20={\displaystyle \frac{1}{2}}=0.5\text{ h } \\ t=t_1-t_2=2-0.5={\displaystyle \frac{3}{2}}=1.5\text{ h } \\ x=t\to \text{ min}=t\cdot 60\text{ min}=1.5\cdot 60\text{ min}=90\text{ min} \end{gathered}$$

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