Ladder 2

Ladder 6.4 meters long is positioned in the well such that its lower end is distanced from the wall of the well 1.2 m. The upper part of the ladder is supported on the upper edge of the well. How high is the well?

Result

x =  6.29 m

Solution:

6.42=x2+1.22 x2=6.42−1.22=39.52 x=39.52=6.29 m6.4^2 = x^2 + 1.2^2 \ \\ x^2 = 6.4^2 - 1.2^2 = 39.52 \ \\ x = \sqrt{ 39.52 } = 6.29 \ \text{m}

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you are crazy

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