# Equations 18023

Solve a system of equations with four unknowns:

2a + 2b-c + d = 4

4a + 3b-c + 2d = 6

8a + 5b-3c + 4d = 12

3a + 3b-2c + 2d = 6

2a + 2b-c + d = 4

4a + 3b-c + 2d = 6

8a + 5b-3c + 4d = 12

3a + 3b-2c + 2d = 6

### Correct answer:

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