# Squares ratio

The first square has a side length of a = 6 cm. The second square has a circumference of 6 dm. Calculate the proportions of the perimeters and the proportions of the contents of these squares? (Write the ratio in the basic form). (Perimeter = 4 * a, content S = a ^ 2)

Result

r1 =  2:5
r2 =  4:25

#### Solution:

$a=6 \ \text{cm} \ \\ o_{2}=6 \ dm=6 \cdot \ 10 \ cm=60 \ cm \ \\ \ \\ o_{2}=4b \ \\ b=o_{2}/4=60/4=15 \ \text{cm} \ \\ o_{1}=4 \cdot \ a=4 \cdot \ 6=24 \ \text{cm} \ \\ \ \\ r_{1}=o_{1}/o_{2}=24/60=\dfrac{ 2 }{ 5 }=0.4=2:5$
$S_{1}=a^2=6^2=36 \ \text{cm}^2 \ \\ S_{2}=b^2=15^2=225 \ \text{cm}^2 \ \\ \ \\ r_{2}=S_{1}/S_{2}=36/225=\dfrac{ 4 }{ 25 }=0.16=4:25$

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