The edge of a cube

How much does the edge of a cube of 54.9 cm3 measure?

Result

a =  3.801 cm

Solution:

V=54.9 cm3 V=a3  a=V3=54.93≐3.8006≐3.801 cmV=54.9 \ \text{cm}^3 \ \\ V=a^3 \ \\ \ \\ a=\sqrt[3]{ V}=\sqrt[3]{ 54.9 } \doteq 3.8006 \doteq 3.801 \ \text{cm}

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