Dairy

Diary workers calculated according to the standards that from the 108 liters of milk is possible to produce 9 kg cheese. How many tons of cheese was possible according to standards make from milk from 100 cows devoted for 30 days with average daily milk yield 10 liters from one cow?

Result

x =  2.5 t

Solution:

s=9/108=1120.0833 kg/l  x1=100 30 10 s=100 30 10 0.0833=2500 kg x=x1t=x1/1000 t=2500/1000 t=2.5 t=52=2.5 ts=9/108=\dfrac{ 1 }{ 12 } \doteq 0.0833 \ \text{kg/l} \ \\ \ \\ x_{1}=100 \cdot \ 30 \cdot \ 10 \cdot \ s=100 \cdot \ 30 \cdot \ 10 \cdot \ 0.0833=2500 \ \text{kg} \ \\ x=x_{1} \rightarrow t=x_{1} / 1000 \ t=2500 / 1000 \ t=2.5 \ t=\dfrac{ 5 }{ 2 }=2.5 \ \text{t}



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