Three numbers

Find three numbers so that the second number is 4 times greater than the first and the third is lower by 5 than the second number. Their sum is 67.

Correct result:

a =  8
b =  32
c =  27

Solution:


b = 4a
c = b - 5
a+b+c=67

b = 4•a
c = b - 5
a+b+c=67

4a-b = 0
b-c = 5
a+b+c = 67

a = 8
b = 32
c = 27

Our linear equations calculator calculates it.



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