Numbers 3032

Find three numbers so that the second number is three times larger than the first and the third is six larger than the second number. Their sum is 62

Correct answer:

a =  8
b =  24
c =  30

Step-by-step explanation:


b=3a
c=b+6
a+b+c=62

b=3·a
c=b+6
a+b+c=62

3a-b = 0
b-c = -6
a+b+c = 62

Row 3 - 1/3 · Row 1 → Row 3
3a-b = 0
b-c = -6
1.333b+c = 62

Pivot: Row 2 ↔ Row 3
3a-b = 0
1.333b+c = 62
b-c = -6

Row 3 - 1/1.33333333 · Row 2 → Row 3
3a-b = 0
1.333b+c = 62
-1.75c = -52.5


c = -52.5/-1.75 = 30
b = 62-c/1.33333333 = 62-30/1.33333333 = 24
a = 0+b/3 = 0+24/3 = 8

a = 8
b = 24
c = 30

Our linear equations calculator calculates it.



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