Sum of squares

If the first number is 80% of the second number and 4 times the sum of their squares is 656, find the numbers.

Correct answer:

a =  8
b =  10

Step-by-step explanation:

r=80%=10080=54=0.8  a=r b 4(a2+b2)=656  4((rb)2+b2)=656 4(r2 b2+b2)=656  b=1+r2656/4=1+0.82656/4=10  a=r b=0.8 10=8



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