Christmas holidays

How many percent take Christmas holidays lasting 18 days from a school year that lasts 303 days? Round the result to two decimal places

Result

p =  5.94 %

Solution:

p=100 18303=6001015.94065.94%p=100 \cdot \ \dfrac{ 18 }{ 303 }=\dfrac{ 600 }{ 101 } \doteq 5.9406 \doteq 5.94 \%



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