Probability 7627

In the monitored group of people, 8% are ill with the flu. One hundred people from this group were examined. What is the probability that at most 5 of them will be sick with the flu?
(round to 3 decimal places)

Correct answer:

p =  17.9876 %

Step-by-step explanation:

q=8/100=252=0.08 w=1q=10.08=2523=0.92 C0(100)=(0100)=0!(1000)!100!=11=1  p0=(0100) q0 w100=1 0.080 0.921000.0002 C1(100)=(1100)=1!(1001)!100!=1100=100  p1=(1100) q1 w99=100 0.081 0.92990.0021 C2(100)=(2100)=2!(1002)!100!=2110099=4950  p2=(2100) q2 w98=4950 0.082 0.92980.009 C3(100)=(3100)=3!(1003)!100!=3211009998=161700  p3=(3100) q3 w97=161700 0.083 0.92970.0254 C4(100)=(4100)=4!(1004)!100!=4321100999897=3921225  p4=(4100) q4 w96=3921225 0.084 0.92960.0536 C5(100)=(5100)=5!(1005)!100!=5432110099989796=75287520  p5=(5100) q5 w95=75287520 0.085 0.92950.0895  p=100 (p0+p1+p2+p3+p4+p5)=100 (0.0002+0.0021+0.009+0.0254+0.0536+0.0895)=17.9876%

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