# The temperature 5

The temperature at 4pm was 53° Fahrenheit the temperature dropped 3° each hour from 4pm to 9pm which equation below accurately represents the temperature at 9pm

Result

t2 =  37 °F

#### Solution:

$t_{1}=52 \ ^\circ \text{F} \ \\ g=3 \ ^\circ \text{F/hr} \ \\ \ \\ t_{2}=t_{1} - g \cdot \ (9-4)=52 - 3 \cdot \ (9-4)=37=37 ^\circ \text{F}$

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