The temperature 5

The temperature at 4pm was 53° Fahrenheit the temperature dropped 3° each hour from 4pm to 9pm which equation below accurately represents the temperature at 9pm


t2 =  37 °F


t1=52 g=3 F/hr  t2=t1g (94)=523 (94)=37=37Ft_{1}=52 \ ^\circ \text{F} \ \\ g=3 \ ^\circ \text{F/hr} \ \\ \ \\ t_{2}=t_{1} - g \cdot \ (9-4)=52 - 3 \cdot \ (9-4)=37=37 ^\circ \text{F}

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