An experiment 2

The temperature of a substance in an experiment changes by -8.7°F from 10 AM to 1 PM At 5 PM, the temperature is 33.5°F. It is 2/3 of what the temperature was at 1 PM.

What was the temperature at 10 AM of the substance?

Correct answer:

t10 =  58.95 °F

Step-by-step explanation:

Δ=8.7 °F t5=33.5 °F  2/3 t1=t5 2/3 t1=33.5  2t1=100.5  t1=4201=50.25  t10=t1Δ=50.25(8.7)=58.95°F

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