Trams 2

Square passes two lines of tram. One running every nine minutes, a second interval of 15 minutes. Exactly at 12 o'clock arrived two tram lines in the square. How soon should a similar situation arise again?

Result

t = 12:45 hh:mm

Solution:

$9 = 3^2 \ \\ 15 = 3 \cdot 5 \ \\ LCM(9, 15) = 3^2 \cdot 5 = 45 \ \\ x = 12+45/60 = 12.75 \ h = 12:45 \ \text{hh}:\text{mm}$

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