Trams 2

Square passes two lines of tram. One running every nine minutes, a second interval of 15 minutes. Exactly at 12 o'clock arrived two tram lines in the square. How soon should a similar situation arise again?

Result

t = 12:45 hh:mm

Solution:

$$\begin{gathered} 9=3^2 \\ 15=3\cdot 5 \\ LCM(9,15)=3^2\cdot 5=45 \\ x=12+45\mathrm{/}60=12.75h=12:45\text{ hh}:\text{mm} \end{gathered}$$

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