Energy consumption

The device is connected to 230V and draws 3.5A current. Power consumption is 1932kJ. How many minutes has this device been in operation?

Correct result:

t =  40 min

Solution:

U=230 V I=3.5 A W=1932 kJ J=1932 1000  J=1932000 J  P=U I=230 3.5=805 W  W=Pt  t1=W/P=1932000/805=2400 s  t=t1 min=t1/60  min=2400/60  min=40 min



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