Energy consumption

The device is connected to 230V and draws 3.5A current. Power consumption is 1932kJ. How many minutes has this device been in operation?

Correct result:

t =  40 min

Solution:

U=230 V I=3.5 A W=1932 kJJ=1932 1000 J=1932000 J  P=U I=230 3.5=805 W  W=Pt  t1=W/P=1932000/805=2400 s  t=t1min=t1/60 min=2400/60 min=40 min=40 minU=230 \ \text{V} \ \\ I=3.5 \ \text{A} \ \\ W=1932 \ kJ \rightarrow J=1932 \cdot \ 1000 \ J=1932000 \ J \ \\ \ \\ P=U \cdot \ I=230 \cdot \ 3.5=805 \ \text{W} \ \\ \ \\ W=Pt \ \\ \ \\ t_{1}=W/P=1932000/805=2400 \ \text{s} \ \\ \ \\ t=t_{1} \rightarrow min=t_{1} / 60 \ min=2400 / 60 \ min=40 \ min=40 \ \text{min}



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