Cooker electrical work

A cooker connected to a 40 V voltage source draws a current of 0.5 A. Determine the amount of electrical work the cooker does in 3 minutes.

Final Answer:

W =  3600 J

Step-by-step explanation:

$$\begin{gathered} U=40\text{V} \\ I=0.5\text{A} \\ t=3\text{min}\to \text{s}=3\cdot 60\text{s}=180\text{s} \\ P=U\cdot I=40\cdot 0.5=20\text{W} \\ W=P\cdot t=20\cdot 180=3600\text{J} \end{gathered}$$

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