Individual 31411

On sources with voltage U = 12V, resistors R1 = 1 Ohm, R2 = 2 Ohm and R3 = 9 Ohm are connected in series. Determine the current I flowing from the source and the voltage drops U1, U2, and U3 on the individual resistors?

Correct answer:

I =  1 A
U1 =  1 V
U2 =  2 V
U3 =  9 V

Step-by-step explanation:

U=12 V R1=1 Ω R2=2 Ω R3=9 Ω  R=R1+R2+R3=1+2+9=12 Ω  I=U/R=12/12=1 A
U1=I R1=1 1=1 V
U2=I R2=1 2=2 V
U3=I R3=1 9=9 V



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