Calculate 80467

Calculate the current I that would race through resistor R5 (720 ohms), resistor R2 (220 ohms), and an LED (U=2V) at a DC 6V source. The resistors are connected in series.

Correct answer:

I =  4.2553 mA

Step-by-step explanation:

R5=720 Ω R2=220 Ω U3=2 V U=6 V  U2=UU3=62=4 V R=R2+R5=220+720=940 Ω  I2=RU2=9404=23510.0043 A  I=I2 1000=0.0043 1000=4.2553 mA



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