Resistor series connection

Three resistors with resistances of 200 Ω, 400 Ω, and 600 Ω are connected in series (in series)—a current of 1.8 A flows through the first 200 Ω resistor.

a) What current passes through the second and what current through the third resistor?
b) What are the electrical voltages across the respective resistors?
c) What is the total resistance of the resistors connected in this way?

Final Answer:

I₂ =  1.8 A
I₃ =  1.8 A
U₁ =  360 V
U₂ =  720 V
U₃ =  1080 V
R =  1200 Ω

Step-by-step explanation:

$$\begin{gathered} I_1=1.8\text{A} \\ {R}_1=200\Omega \\ {R}_2=400\Omega \\ {R}_3=600\Omega \\ {I}_1=I_2=I_3 \\ {I}_2=I_1=1.8=1.8\text{A} \end{gathered}$$

$I_3=I_1=1.8=1.8\text{A}$

$U_1=R_1\cdot I_1=200\cdot 1.8=360\text{V}$

$U_2=R_2\cdot I_2=400\cdot 1.8=720\text{V}$

$U_3=R_3\cdot I_3=600\cdot 1.8=1080\text{V}$

$R=R_1+R_2+R_3=200+400+600=1200\Omega$

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