R1+R2 in parallel

The resistance ratio of the first and second resistors is 3: 1 and the current flowing through the first resistor is 300 mA. What current flows through the second resistor (resistors connected in parallel)?

Correct answer:

I2 =  900 mA

Step-by-step explanation:

R1:R2=3:1 I1=300 mA  R1:R2=I2:I1  I2=I1 3=300 3=900 mA



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