A charge

A charge of 9 C passes through series-connected resistors with resistances of 40 ohms and 60 ohms in 1 minute. a) What voltage are they connected to? b) Calculate the voltage across each resistor.

Final Answer:

U =  15 V
U₁ =  6 V
U₂ =  9 V

Step-by-step explanation:

$$\begin{gathered} R_1=40\Omega \\ {R}_2=60\Omega \\ Q=9\text{C} \\ t=1\text{min}\to \text{s}=1\cdot 60\text{s}=60\text{s} \\ Q=I\cdot t \\ I=Q/t=9/60=\frac{3}{20}=0.15\text{A} \\ {U}_1=R_1\cdot I=40\cdot 0.15=6\text{V} \\ {U}_2=R_2\cdot I=60\cdot 0.15=9\text{V} \\ U=U_1+U_2=6+9=15\text{V} \end{gathered}$$

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