Closed circuit

There is a voltage source with U1 = 12 V in a closed circuit and with internal resistance, R1 = 0.2 Ω. The external resistance is R2 = 19.8 Ω.
Find the electric current and terminal voltage.

Correct answer:

I =  0.6 A
U₂ =  11.88 V

Step-by-step explanation:

$$\begin{gathered} U_1=12\text{V} \\ {R}_1=0.2\Omega \\ {R}_2=19.8\Omega \\ I=\frac{U_1}{R_1+R_2}=\frac{12}{0.2+19.8}=\frac{3}{5}\text{A}=0.6\text{A} \end{gathered}$$

$U_2=I\cdot R_2=0.6\cdot 19.8=11.88\text{V}$

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