Probability - tickets

What is the probability when you have 25 tickets in 5000 that you not wins the first (one) prize?

Result

p =  99.5 %

Solution:

p=100⋅ (1−25/5000)=1992=99.5%p=100 \cdot \ (1-25/5000) = \dfrac{ 199 }{ 2 } = 99.5 \%

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Leave us a comment of this math problem and its solution (i.e. if it is still somewhat unclear...):

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Math student
hello there,

I would like to ask because is not so clear at least to me, why is not 1/200 and it is 199/200 the correct solution?

Regards
Katerina

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