How many cans must be put in the bottom row if we want 182 cans arranged in 13 rows above so that each subsequent row has always been one in less? How many cans will be in the top row?

Correct answer:

a =  20
b =  8

Step-by-step explanation:

s=182 n=13 d=1  s=n(a+b)/2 s=n(a+a+(n1)d)/2  182=13(2an+1)/2 28=2an+1 28=2a12 40=2a a=20
b=201 (131)=8

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