# GP - 8 items

Determine the first eight members of a geometric progression if a9=512, q=2

Correct result:

a1 =  2
a2 =  4
a3 =  8
a4 =  16
a5 =  32
a6 =  64
a7 =  128
a8 =  256

#### Solution:

${a}_{1}=512\mathrm{/}{2}^{9-1}=2$
${a}_{2}=512\mathrm{/}{2}^{9-2}=4$
${a}_{3}=512\mathrm{/}{2}^{9-3}=8$
${a}_{4}=512\mathrm{/}{2}^{9-4}=16$
${a}_{5}=512\mathrm{/}{2}^{9-5}=32$
${a}_{6}=512\mathrm{/}{2}^{9-6}=64$
${a}_{7}=512\mathrm{/}{2}^{9-7}=128$
${a}_{8}=512\mathrm{/}{2}^{9-8}=256$

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