Consecutive numbers

Sum of ten consecutive numbers is 105. Determine these numbers (write first and last).

Correct result:

a1 =  6
a10 =  15

Solution:

d=1 s10=105 s10=10(a1+a10)/2⋅d 210=10(a1+a10) 21=a1+a10=a1+a1+9 12=2a1 a1=12/2=6 
a10=6+(10−1)⋅ 1=15

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